This article is talking about SRPP tube amplifier and touching the key points.

The actual experiment support can prove the theory.

The amp itself is simple just two triodes V1 and V2 connected in series to share one B+ power supply.

Where there is no input signal V1 and V2 have same plate current and half B+ volt supply each.

If there is a positive input signal to V1 grid, they work in two steps, first step the Ip of V1 will

increase and the voltage drop at R_{AK} will increase, this will make the Ip of V2 decrease (second step).

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Then the current difference of two tubes is 2x delta Ip, this 2 delta Ip will go through R_{L} and the output

voltage is doubled in compare with one triode working so that this is a push pull.

Please see picture:

In most cases, we use two identical triodes and R_{K}=R_{AK }so that the bias is equal for two tubes.

The only thing we have to do is to determine the value of R_{K}, R_{AK} and R_{L}.

It is easy to suggest the value of them:

R_{K} could be 5.1 KΩ_{ }for 6SL7 or 1.5 KΩ for 12AU7 and 680 Ω for 6DJ8.

and the R_{L} could be 150 KΩ_{ }to 220 KΩ.

OK, it was done! and it works.

The listening result feedback is different, sometimes excellent, sometimes so far so good and somebody said it is too sharp and a cathode follower should be added to make the sound warmer. What happened?

Is it the R_{K}, R_{AK} and R_{L} value come by guess is not appropriate and has to be fine tuned?

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Actually there are two key points for SRPP amplifier for achieving an excellent result:

1. Static balance: – V1 and V2 should share 1/2 B+ supply each in the case of no input signal.

2. Dynamic balance: – An input signal to V1 grid caused a delta Ip1 for V1, this delta Ip1 will cause a delta Ip2 for V2 because of R_{AK}, it is known as dynamic balance if delta Ip1= delta Ip2.

Both static and dynamic balance ensure the maximum non-distorted output voltage swing in load resistor R_{L}.

The static balance is an easy job that V1 and V2 identical and R_{K} =R_{AK} for same bias, so same Ip and shares 1/2 B+ each tube. The dynamic balance is more important because this is a push-pull operation, this will ensure low distortion voltage output. How to achieve dynamic balance is more complicated, but if we can go step by step with patience we will get it. Ok, let’s go.

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Firstly a balance resistor R should be added at the plate of V2, please see picture:

Where R= R_{AK}= RK, and R_{L} is load resistor. Looking for conditions of dynamic balance we need a mathematical model (equivalent circuit) for help. R_{K} is by-passed and not shown, please see picture:

There are two tubes work together, we can assume only V1 is working while V2 signal is short-circuited and then only V2 is working while V1 signal is short-circuited, then calculate them one by one and add the results together, the sum will be equal to that result of two tubes work together simultaneously(superposition theorem).

V1 working V2 signal short-circuited please see picture:

By Ohm’s law:

V2 working V1 signal short-circuited please see picture:

Now V1 and V2 working together please see picture:

For V2:

From F 6 and F 7:

If we Set:-

And Also Set:-

From F 1 and F 9 :

From F 2 and F 9 :

From F 8 and F 10 :

From F 12 and F 13 :

Then :

From F 11 and F 15 :

Then:

Then:-

Then:

We set :

From F 2 and F 20 :

From F 11 and F 21 :

From F 5 and F 20 :

From F 19 and F 23 :

From F 22 and F 24 :

Since I_{1o}+I_{2o} is the output current so that – (I_{1o}+I_{2o})R_{L} is the output voltage :

Then the voltage gain is :

And so:-

This is the correct formula for SRPP amplifier voltage gain in terms of µ, R_{a}, R and R_{L}.

Please note R_{x}, R_{y} and R_{z} are the resistance of a group of resistors. ( F 9, F 10 and F 20 )

Since the I_{1o} and I_{2o} are the output current of V1 and V2, for dynamic balance, we need:

From F 22, F 24 and F 28:

We have:

And:

And:

From F 9, F 10 and F 32 we have:

Then

Then

Then

And

Then:

And

Thus:

<-F40

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Yes, this is exactly the second order equation:

To find R:

From F 41 and F 42 we have:

Then:

Then:

So simple that this is the relationship between µ, Ra, R and RL for dynamic balance.

Since µ and Ra are fixed for a specified tube so we can choose R or RL first and then calculate the other. In a practical case, the R has to be determined first to obtain the plate current we desired under a preset B+ supply, then get RL by the above formula F 45 and calculate the voltage gain by F 27a.

If V1 and V2 are identical triodes and R = RK = RAK we get static balance.

F 45 is the condition needed to maintain the dynamic balance.

F 27a is the voltage gain relationship with RL, Ra, µ and R

I suppose the above formulas are of no doubt as they were derived step by step. I will build a 6SL7 or 12AX7 SRPP voltage amp to drive a UX-245 triode base on the above calculation on my single end stereo platform.

I select a 12AX7 the databook said that µ = 100 and Ra= 80K ohm I made R = RAK = RK = 3.3 K ohm and find the RL is 123 K ohm by F 45, 120 K is practical.

Now we have:

µ = 100

R_{A}= 80K ohm

R = RAK = RK = 3.3 K ohm

R_{L} = 120 K

By F 27a the gain A = -74.5

Actual oscilloscope test confirms the gain is about 71 OK. The maximum non-distorted output voltage swing is 150 Vpp from a 300 V B+ supply.

Please see the picture below.

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The sound quality is very clear in high frequency and the low is good. So that this is another choice for the driver stage.

Thank you for visiting!

So the main objective of this configuration is to obtain about twice the voltage swing in order to meet high grid to grid voltage swing of low mu triodes, like the 45 or the 2A3 and perhapps to get the even harmonics out, because of push pull output.??